Armstrong Number in C

C program to Check whether a Number is Armstrong or Not

A number is Armstrong, if sum of it’s digit raised to power of total number of digits in that number is equal to the original number .
Example. 
      consider a number 153, it has 3 digits, where  1³+5³+3³=153. Hence 153 is an Armstrong number.

% is the remainder after division (modulo division) arithmetic operator in C.
11 % 5 = 1 (11 / 5 = 2 with remainder 1)

// C program to find Armstrong number

#include <stdio.h>

int power(int x, unsigned int y)
{
    if (y == 0)
        return 1;
    if (y % 2 == 0)
        return power(x, y / 2) * power(x, y / 2);
    return x * power(x, y / 2) * power(x, y / 2);
}

int count(int x)
{
    int n = 0;
    while (x)
    {
        n++;
        x = x / 10;
    }
    return n;
}

int isArmstrong(int x)
{
    int n = count(x);
    int temp = x, sum = 0;
    while (temp)
    {
        int r = temp % 10;
        sum += power(r, n);
        temp = temp / 10;
    }

    if (sum == x)
        return 1;
    else
        return 0;
}

int main()
{
    int num;
    printf("\nEnter the number=");
    scanf("%d", &num);
    if (isArmstrong(num) == 1)
        printf("%d is an Armstrong number\n", num);
    else
        printf("%d is an not Armstrong number\n", num);
    return 0;
}

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